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Min Max solution in Clear category for Min and Max by Piotr.Helminiak
def min(*args, **kwargs):
key = kwargs.get("key", None)
if len(args)==1:
args=list(args[0])
mini=args[0]
if key==None:
for x in args:
if xmaks:
maks=x
else:
for x in args:
if key(x)>key(maks):
maks=x
return maks
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert max(3, 2) == 3, "Simple case max"
assert min(3, 2) == 2, "Simple case min"
assert max([1, 2, 0, 3, 4]) == 4, "From a list"
assert min("hello") == "e", "From string"
assert max(2.2, 5.6, 5.9, key=int) == 5.6, "Two maximal items"
assert min([[1, 2], [3, 4], [9, 0]], key=lambda x: x[1]) == [9, 0], "lambda key"
Oct. 26, 2016
