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First solution in Uncategorized category for Min and Max by Moff
def cmp(x, y, f):
if f(x) > f(y):
return 1
elif f(x) < f(y):
return -1
else:
return 0
def rise(args, kvargs, cmp_res):
iterable = iter(args if len(args) > 1 else args[0])
fun = kvargs.get('key', lambda x: x)
result = next(iterable)
for i in iterable:
if cmp(i, result, fun) == cmp_res:
result = i
return result
def max(*args, **kvargs):
return rise(args, kvargs, 1)
def min(*args, **kvargs):
return rise(args, kvargs, -1)
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert max(3, 2) == 3, "Simple case max"
assert min(3, 2) == 2, "Simple case min"
assert max([1, 2, 0, 3, 4]) == 4, "From a list"
assert min("hello") == "e", "From string"
assert max(2.2, 5.6, 5.9, key=int) == 5.6, "Two maximal items"
assert min([[1, 2], [3, 4], [9, 0]], key=lambda x: x[1]) == [9, 0], "lambda key"
July 17, 2015
