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For else solution in Clear category for Merge Intervals by m.kleinkranenbarg
def merge_intervals(intervals):
"""
Merge overlapped intervals.
"""
result = []
if not intervals:
return result
start, end = intervals[0]
for a, b in intervals[1:]:
if a <= end + 1:
end = max(end, b)
else:
result.append((start, end))
start, end = a, b
else:
result.append((start, end))
return result
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert merge_intervals([(1, 4), (2, 6), (8, 10), (12, 19)]) == [(1, 6), (8, 10), (12, 19)], "First"
assert merge_intervals([(1, 12), (2, 3), (4, 7)]) == [(1, 12)], "Second"
assert merge_intervals([(1, 5), (6, 10), (10, 15), (17, 20)]) == [(1, 15), (17, 20)], "Third"
print('Done! Go ahead and Check IT')
Feb. 12, 2023
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