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First solution in Clear category for Median by lukasz.bogaczynski
def checkio(numbers):
numbers = sorted(numbers)
numbers_count = len(numbers)
half_of_length = int(numbers_count/2)
median = None
if numbers_count % 2 == 0:
median = (numbers[half_of_length] + numbers[half_of_length - 1])/2
else:
median = numbers[half_of_length]
return median
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio([1, 2, 3, 4, 5]) == 3, "Sorted list"
assert checkio([3, 1, 2, 5, 3]) == 3, "Not sorted list"
assert checkio([1, 300, 2, 200, 1]) == 2, "It's not an average"
assert checkio([3, 6, 20, 99, 10, 15]) == 12.5, "Even length"
print("Start the long test")
assert checkio(list(range(1000000))) == 499999.5, "Long."
print("The local tests are done.")
Oct. 19, 2017