Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
First solution in Creative category for Median by enagorny
def checkio(data):
data.sort()
n = len(data)
if n % 2:
return data[n/2]
else:
return sum(data[n/2-1:n/2+1])/2.0
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio([1, 2, 3, 4, 5]) == 3, "Sorted list"
assert checkio([3, 1, 2, 5, 3]) == 3, "Not sorted list"
assert checkio([1, 300, 2, 200, 1]) == 2, "It's not an average"
assert checkio([3, 6, 20, 99, 10, 15]) == 12.5, "Even length"
Feb. 23, 2014
Comments: