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Indented solution in Creative category for Pattern Recognition by veky
def checkio(N, H, R=range, L=len):
for i in R(L(H)):
for j in R(L(H[i])):
I, J = i + L(N), j + L(N[0])
if [r[j:J] for r in H[i:I]] == N:
for k in R(i, I):
for l in R(j, J):
H[k][l] += 2
return H
Feb. 2, 2014
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