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First solution in Clear category for Long Repeat by zafazowany.czarami
import re
def long_repeat(line: str) -> int:
lresult = []
if line == "":
return 0
for letter in set(line):
p = re.compile('{}+'.format(letter),re.IGNORECASE)
res = re.findall(p,line)
lresult+=(res)
print (lresult)
result = len(max(lresult,key=len))
return result
"""
length the longest substring that consists of the same char
"""
# your code here
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert long_repeat('sdsffffse') == 4, "First"
assert long_repeat('ddvvrwwwrggg') == 3, "Second"
assert long_repeat('abababaab') == 2, "Third"
assert long_repeat('aa') == 2, "Third+"
assert long_repeat('') == 0, "Empty"
print('"Run" is good. How is "Check"?')
Nov. 1, 2019
