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Brute force solution solution in Clear category for Long Repeat by frankiser
def long_repeat(line):
"""
Length of the longest substring that consists of the same char
"""
if len(line) > 0:
longest_letter = line[0]
longest_string = 1
else:
longest_letter = ''
longest_string = 0
same_letter_length = 1
for index in range(1,len(line)):
if line[index-1] == line[index]:
same_letter_length += 1
if same_letter_length > longest_string:
longest_string = same_letter_length
longest_letter = line[index]
else:
same_letter_length = 1
return longest_string
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert long_repeat('sdsffffse') == 4, "First"
assert long_repeat('ddvvrwwwrggg') == 3, "Second"
assert long_repeat('abababaab') == 2, "Third"
assert long_repeat('') == 0, "Empty"
print('"Run" is good. How is "Check"?')
March 6, 2019
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