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First solution in Uncategorized category for Index Power by szneqz
def index_power(array, n):
"""
Find Nth power of the element with index N.
"""
if n > (len(array) - 1):
return -1
i = 1
result = 1
while i <= n:
result = result * array[n]
i = i + 1
return result
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert index_power([1, 2, 3, 4], 2) == 9, "Square"
assert index_power([1, 3, 10, 100], 3) == 1000000, "Cube"
assert index_power([0, 1], 0) == 1, "Zero power"
assert index_power([1, 2], 3) == -1, "IndexError"
print("Coding complete? Click 'Check' to review your tests and earn cool rewards!")
Jan. 22, 2018