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Second solution in Clear category for Index Power by narumi.kano.3
index_power = lambda array, n: array[n]**n if len(array)-1 >= n else -1
"""
Find Nth power of the element with index N.
def index_power(array, n):
return -1 if len(array)-1 < n else array[n]**n
...will do.
"""
Jan. 10, 2015
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