Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
Index Power weronika solution in Clear category for Index Power by Weronika.fr
def index_power(array, n):
lenght = len(array)-1
if n > (lenght):
result = (-1)
else:
x = array [n]
result = x**n
return result
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert index_power([1, 2, 3, 4], 2) == 9, "Square"
assert index_power([1, 3, 10, 100], 3) == 1000000, "Cube"
assert index_power([0, 1], 0) == 1, "Zero power"
assert index_power([1, 2], 3) == -1, "IndexError"
Nov. 4, 2016