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any / all solution in Clear category for House Password by vit.aborigen
def checkio(data: str) -> bool:
hasDigit = any(char.isdigit() for char in data)
enoughLen = (len(data) >= 10)
hasUpper = any(char.isupper() for char in data)
hasLower = any(char.islower() for char in data)
return all((hasDigit, hasUpper, hasLower, enoughLen))
Oct. 20, 2018