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Simple solution in Clear category for House Password by makernaren
# migrated from python 2.7
def checkio(data):
b1,b2,b3 = False,False,False
b4 = True if len(data) >= 10 else False
for each in data:
if each.isdigit():
b1 = True
if each.isupper():
b2 = True
if each.islower():
b3 = True
if b1*b2*b3*b4 == 1:
return True
else:
return False
#Some hints
#Just check all conditions
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert checkio('A1213pokl') == False, "1st example"
assert checkio('bAse730onE4') == True, "2nd example"
assert checkio('asasasasasasasaas') == False, "3rd example"
assert checkio('QWERTYqwerty') == False, "4th example"
assert checkio('123456123456') == False, "5th example"
assert checkio('QwErTy911poqqqq') == True, "6th example"
Dec. 27, 2014
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