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First solution in Clear category for House Password by hkaushalya
def checkio(data):
haslen = bool(len(data)>=10)
onedigit = False
onelower = False
oneupper = False
if haslen:
for c in data:
if c.isdigit():
onedigit = True
elif c.islower():
onelower = True
elif c.isupper():
oneupper = True
return (haslen and onedigit and onelower and oneupper)
#Some hints
#Just check all conditions
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert checkio('A1213pokl') == False, "1st example"
assert checkio('bAse730onE4') == True, "2nd example"
assert checkio('asasasasasasasaas') == False, "3rd example"
assert checkio('QWERTYqwerty') == False, "4th example"
assert checkio('123456123456') == False, "5th example"
assert checkio('QwErTy911poqqqq') == True, "6th example"
Aug. 8, 2014