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First solution in Clear category for House Password by LukeMurray
# migrated from python 2.7
def checkio(data):
digitCount = 0
upperCount = 0
lowerCount = 0
if len(data) < 10:
return False
for char in data:
if char.isdigit():
digitCount += 1
if char.islower():
lowerCount += 1
if char.isupper():
upperCount += 1
if digitCount > 0 and upperCount > 0 and lowerCount > 0:
return True
else:
return False
#Some hints
#Just check all conditions
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert checkio('A1213pokl') == False, "1st example"
assert checkio('bAse730onE4') == True, "2nd example"
assert checkio('asasasasasasasaas') == False, "3rd example"
assert checkio('QWERTYqwerty') == False, "4th example"
assert checkio('123456123456') == False, "5th example"
assert checkio('QwErTy911poqqqq') == True, "6th example"
Feb. 24, 2015
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