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First solution in Clear category for House Password by Jay-Jay-D
def checkio(data):
"""
Stephan and Sophia forget about security and use simple passwords for everything.
Help Nikola develop a password security check module.
The password will be considered strong enough if:
- its length is greater than or equal to 10 symbols,
- it has at least one digit,
- one uppercase letter and
- one lowercase letter in it.
The password contains only ASCII latin letters or digits.
:param data: A password as a string.
:return: Is the password safe or not as a boolean or any data type that can be converted and processed as a boolean.
"""
if len(data) < 10:
return False
digit = lower = upper = False
for char in data:
digit = digit or char.isdigit()
lower = lower or char.islower()
upper = upper or char.isupper()
return digit and lower and upper
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert checkio('A1213pokl') == False, "1st example"
assert checkio('bAse730onE4') == True, "2nd example"
assert checkio('asasasasasasasaas') == False, "3rd example"
assert checkio('QWERTYqwerty') == False, "4th example"
assert checkio('123456123456') == False, "5th example"
assert checkio('QwErTy911poqqqq') == True, "6th example"
print("Coding complete? Click 'Check' to review your tests and earn cool rewards!")
Sept. 15, 2018
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