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First solution in Clear category for House Password by AlbertTovmasyan
# migrated from python 2.7
def checkio(password):
cond1 = len(password) >= 10
cond2 = [letter.isdigit() for letter in password]
cond3 = [letter.isalpha() and letter.isupper() for letter in password]
cond4 = [letter.isalpha() and letter.islower() for letter in password]
return cond1 and any(cond2) and any(cond3) and any(cond4)
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert checkio('A1213pokl') == False, "1st example"
assert checkio('bAse730onE4') == True, "2nd example"
assert checkio('asasasasasasasaas') == False, "3rd example"
assert checkio('QWERTYqwerty') == False, "4th example"
assert checkio('123456123456') == False, "5th example"
assert checkio('QwErTy911poqqqq') == True, "6th example"
March 28, 2015