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First solution in Clear category for Group Equal consecutive by ssk8
def group_equal(els):
tmp, grp = [], []
for el in els:
if tmp:
if el == tmp[0]:
tmp.append(el)
else:
grp.append(tmp)
tmp = [el]
else:
tmp.append(el)
if tmp:
grp.append(tmp)
return grp
Dec. 27, 2018
