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Simple solution in Clear category for Group Equal consecutive by mindaugas.dadurkevicius
def group_equal(els):
if els:
return_list = [[els[0]]]
else:
return_list = []
for i in range(1, len(els)):
if els[i] == els[i-1]:
return_list[-1].append(els[i])
else:
return_list.append([els[i]])
return return_list
Dec. 19, 2019