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group_equal_consecutive solution in Clear category for Group Equal consecutive by dannedved
def group_equal(els):
if len(els) == 0:
return []
result = [[els[0]]]
for item in els[1:]:
if item == result[-1][-1]:
result[-1].append(item)
else:
result.append([item])
return result
Sept. 1, 2019
