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First solution in Clear category for Fizz Buzz by vnkvstnk
def checkio(number: int) -> str:
if not (number % 5 or number % 3):
return "Fizz Buzz"
elif not number % 3:
return "Fizz"
elif not number % 5:
return "Buzz"
return str(number)
Sept. 20, 2019
