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First solution in Clear category for Fizz Buzz by furas
#Your optional code here
#You can import some modules or create additional functions
def checkio(number):
result = []
if number%3 == 0:
if number%5 == 0:
return "Fizz Buzz"
else:
return "Fizz"
elif number%5 == 0:
return "Buzz"
return str(number)
#Some hints:
#Convert a number in the string with str(n)
#These "asserts" using only for self-checking and not necessary for auto-testing
April 29, 2014
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