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First solution in Clear category for Fizz Buzz by comet.l
def checkio(number: int) -> str:
if number % 3 == 0 and number%5 == 0:
return "Fizz Buzz"
if number % 3 == 0:
return "Fizz"
if number % 5 == 0:
return "Buzz"
return str(number)
June 12, 2018