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First solution in Uncategorized category for Fizz Buzz by capback250
def checkio(number):
fizzbuzz = []
if number%5 ==0 and number%3 == 0:
return "Fizz Buzz"
elif number%5 == 0:
return "Buzz"
elif number%3 == 0:
return "Fizz"
else:
return str(number)
Feb. 9, 2016