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Fizz Buzz solution in Clear category for Fizz Buzz by W.Zalicki
def checkio(number):
if number % 15 == 0:
return("Fizz Buzz")
elif number % 3 == 0:
return("Fizz")
elif number % 5 == 0:
return("Buzz")
else:
return str(number)
Oct. 15, 2017
