Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
Fizz Buzz solution in Clear category for Fizz Buzz by McDamiozo
def fizzbuzz(number):
if number % 15 == 0:
return 'Fizz Buzz'
elif number % 3 == 0:
return 'Fizz'
elif number % 5 == 0:
return 'Buzz'
else:
return str(number)
def checkio(number):
result = fizzbuzz(number)
return result
return str(number)
if __name__ == '__main__':
assert checkio(15) == "Fizz Buzz", "15 is divisible by 3 and 5"
assert checkio(6) == "Fizz", "6 is divisible by 3"
assert checkio(5) == "Buzz", "5 is divisible by 5"
assert checkio(7) == "7", "7 is not divisible by 3 or 5"
print("Coding complete? Click 'Check' to review your tests and earn cool rewards!")
Oct. 19, 2017