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First solution in Uncategorized category for Fizz Buzz by LT04
def checkio(number):
if number%3 == 0 and number%5 == 0:
return ("Fizz Buzz")
elif number%3 == 0:
return ("Fizz")
elif number%5 == 0:
return ("Buzz")
else:
return str(number)
Oct. 18, 2017