Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
Fizz Buzz solution in Creative category for Fizz Buzz by DenisKnyazev
def checkio(number):
return ("Fizz" * (number % 3 == 0) + " Buzz" * (number % 5 == 0) or str(number)).strip()
if __name__ == '__main__':
assert checkio(15) == "Fizz Buzz", "15 is divisible by 3 and 5"
assert checkio(6) == "Fizz", "6 is divisible by 3"
assert checkio(5) == "Buzz", "5 is divisible by 5"
assert checkio(7) == "7", "7 is not divisible by 3 or 5"
Jan. 4, 2017
Comments:
