First clear solution for Fizz Buzz by Answer.wu - python coding challenges

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First solution in Clear category for Fizz Buzz by Answer.wu

#!_*_coding:utf-8_*_

__author__ = "WuC"

def checkio(n):
    if n%3 == 0 and n%5 == 0:
        return "Fizz Buzz"
    elif n%3 == 0:
        return "Fizz"
    elif n%5 == 0:
        return "Buzz"
    else:
        return str(n)

# Some hints:
# Convert a number in the string with str(n)

# These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
    assert checkio(15) == "Fizz Buzz", "15 is divisible by 3 and 5"
    assert checkio(6) == "Fizz", "6 is divisible by 3"
    assert checkio(5) == "Buzz", "5 is divisible by 5"
    assert checkio(7) == "7", "7 is not divisible by 3 or 5"
    print("Coding complete? Click 'Check' to review your tests and earn cool rewards!")

Aug. 17, 2018

Comments:

Cherubim on Oct. 14, 2018, 6:05 p.m.
<p>Hi, instead of `if n%3 == 0 and n%5 == 0:` you can just use `if n%15 == 0:` :-)</p>

Strings and Integers

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