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First solution in Clear category for Find Sequence by juestr
from functools import reduce
from operator import eq
def checkio(matrix):
n = len(matrix)
r = { 0: range(n), 1: range(n-3), -1: range(n-3, n) }
def check(dx=0, dy=0):
for y in r[dy]:
for x in r[dx]:
span = [matrix[y+dy*i][x+dx*i] for i in range(4)]
if span == [span[0]] * 4:
return True
return False
return check(dx=1) or check(dy=1) or check(dx=1, dy=1) or check(dx=-1, dy=1)
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert checkio([
[1, 2, 1, 1],
[1, 1, 4, 1],
[1, 3, 1, 6],
[1, 7, 2, 5]
]) == True, "Vertical"
assert checkio([
[7, 1, 4, 1],
[1, 2, 5, 2],
[3, 4, 1, 3],
[1, 1, 8, 1]
]) == False, "Nothing here"
assert checkio([
[2, 1, 1, 6, 1],
[1, 3, 2, 1, 1],
[4, 1, 1, 3, 1],
[5, 5, 5, 5, 5],
[1, 1, 3, 1, 1]
]) == True, "Long Horizontal"
assert checkio([
[7, 1, 1, 8, 1, 1],
[1, 1, 7, 3, 1, 5],
[2, 3, 1, 2, 5, 1],
[1, 1, 1, 5, 1, 4],
[4, 6, 5, 1, 3, 1],
[1, 1, 9, 1, 2, 1]
]) == True, "Diagonal"
April 11, 2019
