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First solution in Clear category for Feed Pigeons by kamilinho20
def checkio(number):
birds = 0
i = 0
fedbirds = []
while number > 0:
i += 1
for j in range(birds):
number -= 1
try:
fedbirds.pop(j)
except:
1+1
fedbirds.append(j)
if number == 0:
break
birds += i
return len(fedbirds)
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
#assert checkio(3) == 2, "1st example"
#assert checkio(2) == 1, "2nd example"
#assert checkio(5) == 3, "3rd example"
assert checkio(10) == 6, "4th example"
Dec. 22, 2016