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eaterative solution in Clear category for Feed Pigeons by Tical_1000
def checkio(number):
if number == 1:
return 1
pigeons, i, j = [1], 2, 1
while True:
for n in range(len(pigeons)):
pigeons[n] += (n+1)
eaten = sum(pigeons)
if eaten + i == number:
return j + i
elif eaten + i < number:
pigeons.append(i)
j += i
i += 1
elif eaten >= number:
return j
else:
return number - eaten + j
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert checkio(1) == 1, "1st example"
assert checkio(2) == 1, "2nd example"
assert checkio(5) == 3, "3rd example"
assert checkio(10) == 6, "4th example"
assert checkio(18) == 8, "5th example"
April 14, 2019
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