9-liner: Feed Pigeons the right way! clear solution for Feed Pigeons by Stensen - python coding challenges

Enable Javascript in your browser and then refresh this page, for a much enhanced experience.

9-liner: Feed Pigeons the right way! solution in Clear category for Feed Pigeons by Stensen

def checkio(N):
    count, answer = 0, []
    while sum(answer if answer else [0]) < N:
        count += 1
        answer.extend([0]*count)
        for i in range(len(answer)):
            if sum(answer) < N: answer[i] += 1
            else: break
    return len(list(filter(None, answer)))

Nov. 8, 2020

Comments:

Phil15 on Nov. 9, 2020, 10:40 a.m.
<pre class='brush: python'>while sum(answer) < N: # sum(answer if answer else [0]) len(list(filter(None, answer))) # It count the number of true elements so equivalent to sum(map(bool, answer)) </pre>

Stensen on Nov. 9, 2020, 5:58 p.m.
I really liked this manipulation: <pre class='brush: python'>sum(map(bool, answer)) </pre> Thank you man for letting me know, you are the best!

Phil15 on Nov. 9, 2020, 9:14 p.m.
I feel I rarely use filter. Mostly because I don't put lambda function in it, since list/set/dict/generator comprehension is fine. Second because when I filter, I probably do more than that and ends using comprehension too. I use much more `map` like here or something like `list(map(list, grid2D))` or `'\n'.join(map(''.join, grid2D))`, still with no lambda function.

Ice Base

0 %

You ClassRoom Demo is Ready With the new tool CheckiO ClassRoom, you will be able to analyze your students' progress, have your own leaderboard, change missions order on the map, and so on.