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2-liner - Converting str into time object and then constructing str back solution in Clear category for Date and Time Converter by Pelmen323
import time
import calendar
def date_time(time_str: str) -> str:
z = list(time.strptime(time_str, "%d.%m.%Y %H:%M"))
return "{} {} {} {} {} {} {} {}".format(z[2], calendar.month_name[z[1]], z[0], "year", z[3], "hour" if z[3] == 1 else "hours", z[4], "minute" if z[4] == 1 else "minutes")
# 1. Created a time object to operate with a list of integers
# 2. Created a string using.format with some conditions for singular hour/minute, used calendar to get month name
if __name__ == "__main__":
print("Example:")
print(date_time("01.01.2000 00:00"))
# These "asserts" using only for self-checking and not necessary for auto-testing
assert (
date_time("01.01.2000 00:00") == "1 January 2000 year 0 hours 0 minutes"
), "Millenium"
assert (
date_time("09.05.1945 06:30") == "9 May 1945 year 6 hours 30 minutes"
), "Victory"
assert (
date_time("20.11.1990 03:55") == "20 November 1990 year 3 hours 55 minutes"
), "Somebody was born"
print("Coding complete? Click 'Check' to earn cool rewards!")
Aug. 23, 2021