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Simple and clear solution in Clear category for Moore Neighbourhood by stilus2011
def count_neighbours(grid, row, col, *, counter = 0):
coords = [(row-1,col-1),(row-1,col),(row-1,col+1),
(row,col-1),(row,col+1),
(row+1,col-1),(row+1,col),(row+1,col+1)]
for row, col in coords:
if row in range(len(grid)) and col in range(len(grid[0])):
counter += grid[row][col]
return counter
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert count_neighbours(((1, 0, 0, 1, 0),
(0, 1, 0, 0, 0),
(0, 0, 1, 0, 1),
(1, 0, 0, 0, 0),
(0, 0, 1, 0, 0),), 1, 2) == 3, "1st example"
assert count_neighbours(((1, 0, 0, 1, 0),
(0, 1, 0, 0, 0),
(0, 0, 1, 0, 1),
(1, 0, 0, 0, 0),
(0, 0, 1, 0, 0),), 0, 0) == 1, "2nd example"
assert count_neighbours(((1, 1, 1),
(1, 1, 1),
(1, 1, 1),), 0, 2) == 3, "Dense corner"
assert count_neighbours(((0, 0, 0),
(0, 1, 0),
(0, 0, 0),), 1, 1) == 0, "Single"
Jan. 5, 2016