Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
First solution in Clear category for Moore Neighbourhood by flytaly
def count_neighbours(grid, row, col):
result = 0
for i in range(-1,2):
for j in range(-1,2):
if (row+i in range(0,len(grid)) and
col+j in range(0,len(grid[0])) and
not (i == j == 0)):
if grid[row+i][col+j]:
result += 1
return result
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert count_neighbours(((1, 0, 0, 1, 0),
(0, 1, 0, 0, 0),
(0, 0, 1, 0, 1),
(1, 0, 0, 0, 0),
(0, 0, 1, 0, 0),), 1, 2) == 3, "1st example"
assert count_neighbours(((1, 0, 0, 1, 0),
(0, 1, 0, 0, 0),
(0, 0, 1, 0, 1),
(1, 0, 0, 0, 0),
(0, 0, 1, 0, 0),), 0, 0) == 1, "2nd example"
assert count_neighbours(((1, 1, 1),
(1, 1, 1),
(1, 1, 1),), 0, 2) == 3, "Dense corner"
assert count_neighbours(((0, 0, 0),
(0, 1, 0),
(0, 0, 0),), 1, 1) == 0, "Single"
March 11, 2015
Comments:
