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One liner solution in Clear category for Count Inversions by CDG.Axel
def count_inversion(sequence):
""" Count inversions in a sequence of numbers """
return sum(a > b for i, a in enumerate(sequence, 1) for b in sequence[i:])
if __name__ == '__main__':
print("Example:");
print(count_inversion([1, 2, 5, 3, 4, 7, 6]));
#These "asserts" using only for self-checking and not necessary for auto-testing
assert count_inversion((1, 2, 5, 3, 4, 7, 6)) == 3, "Example"
assert count_inversion((0, 1, 2, 3)) == 0, "Sorted"
assert count_inversion((99, -99)) == 1, "Two numbers"
assert count_inversion((5, 3, 2, 1, 0)) == 10, "Reversed"
print("Coding complete? Click 'Check' to review your tests and earn cool rewards!")
Feb. 26, 2022
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