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dict.get() + dict comprehension solution in Clear category for Convert and Aggregate by Molot
def conv_aggr(data: list[tuple[str, int]]) -> dict[str, int]:
d = dict()
for k,v in data:
d[k] = d.get(k, 0) + v
return {k:v for k,v in d.items() if v and k}
print("Example:")
print(conv_aggr([("a", 7), ("b", 8), ("a", 10)]))
assert conv_aggr([("a", 7), ("b", 8), ("a", 10)]) == {"a": 17, "b": 8}
assert conv_aggr([]) == {}
assert conv_aggr([("a", 5), ("a", -5)]) == {}
assert conv_aggr([("a", 5), ("a", 5), ("a", 0)]) == {"a": 10}
assert conv_aggr([("a", 5), ("", 15)]) == {"a": 5}
print("The mission is done! Click 'Check Solution' to earn rewards!")
Dec. 2, 2022
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