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First solution in Clear category for Convert and Aggregate by Moff
def conv_aggr(data: list[tuple[str, int]]) -> dict[str, int]:
result = dict()
for k, v in data:
result[k] = v + result.get(k, 0)
return {k: v for k, v in result.items() if k and v}
Sept. 10, 2022
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