Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
First solution in Creative category for Brackets by makstheimba
def checkio(expression):
brackets = []
for item in expression:
if item in '({[':
brackets.append(ord(item))
elif item in ')}]':
if not brackets or ord(item)-1-ord(item)//90 != brackets [-1]:
return False
else:
brackets.pop()
return not any(brackets)
March 15, 2015