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ELECTRONIC STATION - "Brackets" solution in Uncategorized category for Brackets by jsg-inet
def checkio(expression):
#print()
#print('new expression: '+expression)
brackets_dict = { '(':')', '[':']', '{':'}'}
open_set = set(brackets_dict.keys())
close_set = set(brackets_dict.values())
open_list = []
for x in expression:
#print(open_list)
if x in open_set:
open_list.append(x)
if x in close_set:
try:
if x==brackets_dict[open_list[-1]]:
open_list.pop()
else:
return False
except:
return False
#print(open_list)
if len(open_list)==0:
return True
else:
return False
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio("((5+3)*2+1)") == True, "Simple"
assert checkio("{[(3+1)+2]+}") == True, "Different types"
assert checkio("(3+{1-1)}") == False, ") is alone inside {}"
assert checkio("[1+1]+(2*2)-{3/3}") == True, "Different operators"
assert checkio("(({[(((1)-2)+3)-3]/3}-3)") == False, "One is redundant"
assert checkio("2+3") == True, "No brackets, no problem"
July 2, 2021