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First solution in Clear category for Brackets by jacekgrycza
def checkio(e):
x=[]
for i in e:
if i=='(' or i==')' or i=='[' or i==']' or i=='{' or i=='}':
x.append(i)
while(len(x)>0):
t=0
for i in range(0, len(x)-1):
if((x[i]=='(' and x[i+1]==')') or (x[i]=='[' and x[i+1]==']') or (x[i]=='{' and x[i+1]=='}')):
del x[i]
del x[i]
t=1
break
if t==0:
return False
return True
Oct. 21, 2016