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Brackets solution in Clear category for Brackets by bart.moura
def checkio(expression):
a = "".join(x for x in expression if x in "{}()[]")
while ("()" in a) or ("[]" in a) or ("{}" in a):
a = a.replace("()","")
a = a.replace("{}","")
a = a.replace("[]","")
return True if a == '' else False
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio("((5+3)*2+1)") == True, "Simple"
assert checkio("{[(3+1)+2]+}") == True, "Different types"
assert checkio("(3+{1-1)}") == False, ") is alone inside {}"
assert checkio("[1+1]+(2*2)-{3/3}") == True, "Different operators"
assert checkio("(({[(((1)-2)+3)-3]/3}-3)") == False, "One is redundant"
assert checkio("2+3") == True, "No brackets, no problem"
Oct. 16, 2020
