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Stack and ord() operations solution in Creative category for Brackets by andrelinod
def checkio(expression):
exp_op = []
for i in expression:
if i in '()[]{}':
if (len(exp_op) == 0) or not (1 <= ord(i) - ord(exp_op[-1]) <= 2):
exp_op.append(i)
else:
exp_op.pop()
return len(exp_op) == 0
# These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == "__main__":
assert checkio("((5+3)*2+1)") == True, "Simple"
assert checkio("{[(3+1)+2]+}") == True, "Different types"
assert checkio("(3+{1-1)}") == False, ") is alone inside {}"
assert checkio("[1+1]+(2*2)-{3/3}") == True, "Different operators"
assert checkio("(({[(((1)-2)+3)-3]/3}-3)") == False, "One is redundant"
assert checkio("2+3") == True, "No brackets, no problem"
Aug. 29, 2022
