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First solution in Uncategorized category for Brackets by adrian.wawrzak
def checkio(expression):
stack = []
for bracket in expression:
if bracket == '{' or bracket == '[' or bracket == '(':
stack.append(bracket)
if bracket == '}':
if stack and stack.pop() == '{':
pass
else:
return False
if bracket == ']':
if stack and stack.pop() == '[':
pass
else:
return False
if bracket == ')':
if stack and stack.pop() == '(':
pass
else:
return False
if stack: return False
return True
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio("((5+3)*2+1)") == True, "Simple"
assert checkio("{[(3+1)+2]+}") == True, "Different types"
assert checkio("(3+{1-1)}") == False, ") is alone inside {}"
assert checkio("[1+1]+(2*2)-{3/3}") == True, "Different operators"
assert checkio("(({[(((1)-2)+3)-3]/3}-3)") == False, "One is redundant"
assert checkio("2+3") == True, "No brackets, no problem"
Nov. 16, 2015