Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
First solution in Uncategorized category for Brackets by RomaN
def checkio(expression):
import re
a = ''.join(re.findall('([(){}[\]])', expression))
while '()' in a or '{}' in a or '[]' in a:
a = a.replace('()', '')
a = a.replace('[]', '')
a = a.replace('{}', '')
return not a
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio("((5+3)*2+1)") == True, "Simple"
assert checkio("{[(3+1)+2]+}") == True, "Different types"
assert checkio("(3+{1-1)}") == False, ") is alone inside {}"
assert checkio("[1+1]+(2*2)-{3/3}") == True, "Different operators"
assert checkio("(({[(((1)-2)+3)-3]/3}-3)") == False, "One is redundant"
assert checkio("2+3") == True, "No brackets, no problem"
March 6, 2016
