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First Regex based solution solution in Clear category for Brackets by Molot
import re
def checkio(expression):
s = ''.join(re.findall(r'[\[|\]|\(|\)|\{|\}]+', expression))
s_ = s
while s:
s = re.sub(r'\(\)|\[\]|\{\}', '', s)
if s == s_: return False
s_ = s
return True
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio("((5+3)*2+1)") == True, "Simple"
assert checkio("{[(3+1)+2]+}") == True, "Different types"
assert checkio("(3+{1-1)}") == False, ") is alone inside {}"
assert checkio("[1+1]+(2*2)-{3/3}") == True, "Different operators"
assert checkio("(({[(((1)-2)+3)-3]/3}-3)") == False, "One is redundant"
assert checkio("2+3") == True, "No brackets, no problem"
July 9, 2018
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