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First solution in Speedy category for Brackets by MaximLialin
def checkio(expression):
line = "".join(i for i in expression if i in "(){}[]" )
while "{}" in line or "[]" in line or "()" in line:
line = line.replace("()","").replace("{}","").replace("[]","")
if line == "":
return True
return False
if __name__ == '__main__':
assert checkio("((5+3)*2+1)") == True, "Simple"
assert checkio("[(3)+(-1)]*{3}") == True, "Simple2"
assert checkio("{[(3+1)+2]+}") == True, "Different types"
assert checkio("(3+{1-1)}") == False, ") is alone inside {}"
assert checkio("[1+1]+(2*2)-{3/3}") == True, "Different operators"
assert checkio("(({[(((1)-2)+3)-3]/3}-3)") == False, "One is redundant"
assert checkio("2+3") == True, "No brackets, no problem"
May 13, 2018
