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Brackets solution in Clear category for Brackets by Druggist
import re
def checkio(expression):
expression = re.sub("([0-9\*\+\-\/])+","",expression)
i = 1
if len(expression)%2 == 1:
return False
while len(expression) > 0:
if expression[0] == ")" or expression[0] == "]" or expression[0] == "}":
return False
if expression[i] == ")":
if expression[i-1] != "(":
return False
else:
expression = expression[:i-1] + expression[i+1:]
i = 0
elif expression[i] == "]":
if expression[i-1] != "[":
return False
else:
expression = expression[:i-1] + expression[i+1:]
i = 0
elif expression[i] == "}":
if expression[i-1] != "{":
return False
else:
expression = expression[:i-1] + expression[i+1:]
i = 0
i += 1
return True
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio("((5+3)*2+1)") == True, "Simple"
assert checkio("{[(3+1)+2]+}") == True, "Different types"
assert checkio("(3+{1-1)}") == False, ") is alone inside {}"
assert checkio("[1+1]+(2*2)-{3/3}") == True, "Different operators"
assert checkio("(({[(((1)-2)+3)-3]/3}-3)") == False, "One is redundant"
assert checkio("2+3") == True, "No brackets, no problem"
Nov. 26, 2016