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First solution in Creative category for Brackets by AlexeyYurko
def checkio(string):
string = ''.join(char for char in string if char in '{}[]()')
while '()' in string or '{}' in string or '[]' in string:
string = string.replace('()', '')
string = string.replace('{}', '')
string = string.replace('[]', '')
return False if string else True
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio("((5+3)*2+1)") == True, "Simple"
assert checkio("{[(3+1)+2]+}") == True, "Different types"
assert checkio("(3+{1-1)}") == False, ") is alone inside {}"
assert checkio("[1+1]+(2*2)-{3/3}") == True, "Different operators"
assert checkio("(({[(((1)-2)+3)-3]/3}-3)") == False, "One is redundant"
assert checkio("2+3") == True, "No brackets, no problem"
April 20, 2018